# How to write armstrong number program in java

A positive integer is called an Armstrong number of order n if abcd Now, the last digit of copyOfInpuit will be truncated by diving it with Then, the last digit is removed from originalNumber after division by Visit this page to learn, how you can display all armstrong numbers between two intervals.

Finally, we check if sum equals the input number. When it is zero, all the digits would have been processed. This variable will hold the sum of the digits raised to the appropriate powers. Then, remainder is powered by 3 number of digits using Math.

Java Program to Check Armstrong Number In this program, you'll learn to check whether a given number is armstrong number or not. This function returns a double value which we explicitly cast to an int so that we can add it to the existing sum.

### Write a java code to input and show it is a armstrong number or not

Beginner Friendly Tutorials for Programmers What do you want to learn today? This function returns a double value which we explicitly cast to an int so that we can add it to the existing sum. You'll learn to do this by using a for loop and a while loop in Java. We represent the number as nxnx-1nx To do so, we construct a String by concatenating the input number with a null string. To extract the last digit of the number, we find the remainder obtained don dividing that number by 10 using the modulo operator. It is the condensed form of: for ;originalNumber! Given below is the complete code for this program. The length of the resultant string obtaining using the length method will give us the number of digits in the input number. This is because, we need to compare the values of final number and original number at the end. Java Program to Check Armstrong Number In this program, you'll learn to check whether a given number is armstrong number or not. Java Examples. Then, remainder is powered by 3 number of digits using Math. The remainder is raised to the power numberOfDigits using the Math. To be more clear, let the number be n and the number of digits be x.

If not, it isn't. We first find the number of digits in the input number. We make a copy of that input and store it in copyOfInput. Given below is the complete code for this program.

### 4 digit armstrong number in java

Visit this page to learn, how you can display all armstrong numbers between two intervals. The remainder is raised to the power numberOfDigits using the Math. The length of the resultant string obtaining using the length method will give us the number of digits in the input number. On each iteration, the last digit of num is stored in remainder. In this program, instead of using while loop, we've used two for loops. If not, it isn't. Next, in a while loop, we extract the digits of the input from right to left, raise them to the appropriate power and add to the existing value of sum. Then, remainder is powered by 3 number of digits using Math. It is required that we make a copy because the number to be checked will be changed during the execution of the program and towards the end, we need the original input number to declare whether it is an Armstrong number or not.
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